F(x)=5(1/2)^x+3

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Solution for F(x)=5(1/2)^x+3 equation: 



(F)=5(1/2)^F+3

We move all terms to the left:

(F)-(5(1/2)^F+3)=0



Domain of the equation: 2)^F+3)!=0

F!=0/1

F!=0

F∈R



We add all the numbers together, and all the variables

F-(5(+1/2)^F+3)=0

We multiply all the terms by the denominator


F*2)^F+3)-(5(+1=0

Wy multiply elements

2F^2+1=0

a = 2; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·2·1
Δ = -8
Delta is less than zero, so there is no solution for the equation

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